Example — Radioactive decay

A radioactive sample follows N(t)=λN(t)N'(t) = -\lambda N(t), with λ>0\lambda>0 the decay constant.

Solution: N(t)=N0eλtN(t) = N_0\,e^{-\lambda t}.

The half-life T1/2T_{1/2} is the time for which N(T1/2)=N0/2N(T_{1/2}) = N_0/2. From eλT1/2=1/2e^{-\lambda T_{1/2}} = 1/2 we obtain λT1/2=ln2\lambda T_{1/2} = \ln 2, that is: T1/2=ln2λ\boxed{T_{1/2} = \frac{\ln 2}{\lambda}}

The curve N/N0=eλtN/N_0 = e^{-\lambda t} decreases exponentially; the dashed line marks the level 1/21/2 reached at t=T1/2t = T_{1/2}.

Exponential decay: the fraction of remaining nuclei N/N0N/N_0 halves after each time T1/2T_{1/2}.

Topics: Differential equations
Concepts: Decay · Half-life · Separable variables
Functions: Exponential function
Skills: Integrating · Modelling