Text Compute the following definite integrals: (a) ∫13x2 dx\displaystyle\int_1^3 x^{2}\,dx∫13x2dx (b) ∫02(3x2+1) dx\displaystyle\int_0^2 (3x^{2}+1)\,dx∫02(3x2+1)dx (c) ∫14x dx\displaystyle\int_1^4 \sqrt{x}\,dx∫14xdx Solution (a) [x33]13=263≈8.667\Big[\tfrac{x^{3}}{3}\Big]_1^3=\dfrac{26}{3}\approx8.667[3x3]13=326≈8.667. (b) [x3+x]02=10\big[x^{3}+x\big]_0^2=10[x3+x]02=10. (c) [23x3/2]14=143≈4.667\Big[\tfrac23 x^{3/2}\Big]_1^4=\dfrac{14}{3}\approx4.667[32x3/2]14=314≈4.667. a=263≈8.667; b=10; c=143≈4.667\boxed{a=\tfrac{26}{3}\approx8.667;\ b=10;\ c=\tfrac{14}{3}\approx4.667}a=326≈8.667; b=10; c=314≈4.667