Locating inflection points is entirely analogous to locating maxima and minima, but with the second derivative in place of the first: we look for the points where ff'' vanishes and check that it changes sign.

Property — How to find inflection points

  1. Compute f(x)f''(x).
  2. Find the points where f(x)=0f''(x)=0 (or where ff'' does not exist).
  3. Check that ff'' changes sign around that point. If it does: inflection point. If not: it is not an inflection point (it is a point where the concavity “pauses” but does not change).

The third step is essential: as for extrema, the vanishing of ff'' is only a necessary condition. If ff'' does not change sign, the concavity stays the same and the point is not an inflection point.

Example

Let us look for the inflection points of f(x)=2x+1x2f(x) = \dfrac{2x+1}{x^2}. The first derivative f(x)=2x22x3=2x+2x3f'(x) = -\dfrac{2}{x^2}-\dfrac{2}{x^3} = -\dfrac{2x+2}{x^3} vanishes at x=1x=-1 (a stationary point, to be classified by studying the sign of ff'). The second derivative is f(x)=4x3+6x4=4x+6x4,f=0    x=32.f''(x) = \frac{4}{x^3}+\frac{6}{x^4} = \frac{4x+6}{x^4}, \qquad f''=0 \iff x = -\frac{3}{2}. Since x4>0x^4>0, the sign of ff'' is that of 4x+64x+6: for x<32x < -\tfrac{3}{2} we have f<0f''<0 (concave), for 32<x<0-\tfrac{3}{2} < x < 0 we have f>0f''>0 (convex). The concavity changes, so x=32x=-\dfrac{3}{2} is an inflection point.

Topics: Curve sketching
Concepts: Concavity and convexity · Second derivative · Inflection point
Skills: Sketching a function