Text Compute the derivative of each function: (a) y=(x2+2)(x+3)y=(x^{2}+2)(x+3)y=(x2+2)(x+3) (b) y=x2+32x−1y=\dfrac{x^{2}+3}{2x-1}y=2x−1x2+3 (c) y=xx2+1y=\dfrac{x}{x^{2}+1}y=x2+1x Solution (a) Product rule: y′=2x(x+3)+(x2+2)=3x2+6x+2y'=2x(x+3)+(x^{2}+2)=3x^{2}+6x+2y′=2x(x+3)+(x2+2)=3x2+6x+2. (b) Quotient rule: y′=2x(2x−1)−(x2+3)⋅2(2x−1)2=2x2−2x−6(2x−1)2y'=\dfrac{2x(2x-1)-(x^{2}+3)\cdot 2}{(2x-1)^{2}}=\dfrac{2x^{2}-2x-6}{(2x-1)^{2}}y′=(2x−1)22x(2x−1)−(x2+3)⋅2=(2x−1)22x2−2x−6. (c) y′=(x2+1)−x⋅2x(x2+1)2=1−x2(x2+1)2y'=\dfrac{(x^{2}+1)-x\cdot 2x}{(x^{2}+1)^{2}}=\dfrac{1-x^{2}}{(x^{2}+1)^{2}}y′=(x2+1)2(x2+1)−x⋅2x=(x2+1)21−x2.