Statement Compute the derivative of y=ln2(2x+5)=[ln(2x+5)]2y=\ln^{2}(2x+5)=\big[\ln(2x+5)\big]^{2}y=ln2(2x+5)=[ln(2x+5)]2. Solution Chain rule with the power rule: y′=2ln(2x+5)⋅12x+5⋅2=4 ln(2x+5)2x+5.y'=2\ln(2x+5)\cdot\frac{1}{2x+5}\cdot 2=\frac{4\,\ln(2x+5)}{2x+5}.y′=2ln(2x+5)⋅2x+51⋅2=2x+54ln(2x+5).