Text Compute the derivative of each function: (a) y=x4−3x2+7y=x^{4}-3x^{2}+7y=x4−3x2+7 (b) y=(2x−1)5y=(2x-1)^{5}y=(2x−1)5 (c) y=1x2+1y=\dfrac{1}{x^{2}+1}y=x2+11 (d) y=xx+1y=x\sqrt{x+1}y=xx+1 Solution (a) y′=4x3−6xy'=4x^{3}-6xy′=4x3−6x. (b) y′=10(2x−1)4y'=10(2x-1)^{4}y′=10(2x−1)4. (c) y′=−2x(x2+1)2y'=-\dfrac{2x}{(x^{2}+1)^{2}}y′=−(x2+1)22x. (d) y′=x+1+x2x+1=3x+22x+1y'=\sqrt{x+1}+\dfrac{x}{2\sqrt{x+1}}=\dfrac{3x+2}{2\sqrt{x+1}}y′=x+1+2x+1x=2x+13x+2.