Piecewise-defined functions change formula at certain points. Precisely at these junction points continuity is not automatic and must be verified with the one-sided limits.

Remark — How to verify continuity at the junction point

Given f(x)={g(x)x<x0h(x)xx0f(x) = \begin{cases} g(x) & x < x_0 \\ h(x) & x \ge x_0 \end{cases} the function is continuous at x0x_0 if and only if: limxx0g(x)=limxx0+h(x)=h(x0).\lim_{x\to x_0^-}g(x) = \lim_{x\to x_0^+}h(x) = h(x_0). That is: the limit from the left (with the left-hand formula) must coincide with the limit from the right (with the right-hand formula) and with the value at x0x_0.

In practice one computes three quantities — left limit, right limit and value of the function at the point — and imposes that they all be equal. If parameters appear, this condition provides an equation that allows them to be determined.

Topics: Continuita
Concepts: Continuita · Funzione definita a tratti · Limite destro e sinistro
Skills: Ragionare per casi