a) The function xx=exlnx is continuous for x>0; hence limx→1+xx=11=1.
b) Set t=x−1→0−: tsint→1 (notable limit). So the limit is 1.
c) Compare degrees: in the numerator the dominant term is −x2 (degree 2), in the denominator −3x3 (degree 3). Since the denominator grows faster,
−3x3−x2=3x1→0.
a=1, b=1, c=0