Statement The arithmetic mean of FnF_nFn and LnL_nLn is Fn+1F_{n+1}Fn+1. Verify it for n=6n=6n=6. Solution With n=6n=6n=6: F6=8F_6=8F6=8 and L6=18L_6=18L6=18, so F6+L62=8+182=262=13=F7.\frac{F_6+L_6}{2}=\frac{8+18}{2}=\frac{26}{2}=\boxed{13}=F_7.2F6+L6=28+18=226=13=F7.