In a right-angled triangle the trigonometric functions take on an immediate meaning: they are simple ratios between the sides. This is the starting point for solving any triangle.

Property — Relations in right-angled triangles

Let ABCABC be a right-angled triangle with the right angle at CC, legs a=BCa = BC, b=ACb = AC, hypotenuse c=ABc = AB, angle α=BAC^\alpha = \widehat{BAC} opposite the leg aa, angle β=ABC^\beta = \widehat{ABC} opposite the leg bb. Then:

\sin\alpha &= \frac{\text{cateto opposto ad }\alpha}{\text{ipotenusa}} = \frac{a}{c}, & \cos\alpha &= \frac{\text{cateto adiacente ad }\alpha}{\text{ipotenusa}} = \frac{b}{c}, \\ \tan\alpha &= \frac{\text{cateto opposto}}{\text{cateto adiacente}} = \frac{a}{b}. \end{aligned}$$ With analogous formulae for $\beta$, swapping the roles of $a$ and $b$.

These formulae generalise the definition of sin\sin, cos\cos, tan\tan given on the trigonometric circle: the right-angled triangle with vertices OO, PαP_\alpha and the projection of PαP_\alpha onto the xx-axis has hypotenuse 11 (the radius), and its legs are cosα\cos\alpha (horizontal) and sinα\sin\alpha (vertical).

Topics: Triangle trigonometry
Concepts: Triangle solving · Right-angled triangle
Functions: Cosine · Sine · Tangent
Skills: Synthetic geometry · Using formulae