An example shows how the sum-to-product formulae turn a sum into a product and open the way to solving an equation.

Example — Factorising

Factorise sin(3x)+sinx\sin(3x) + \sin x into a product.

With p=3xp=3x and q=xq=x: sin(3x)+sinx=2sin ⁣(3x+x2)cos ⁣(3xx2)=2sin(2x)cosx.\sin(3x) + \sin x = 2\sin\!\left(\tfrac{3x+x}{2}\right)\cos\!\left(\tfrac{3x-x}{2}\right) = 2\sin(2x)\cos x. This factorisation is extremely useful for solving the equation sin(3x)+sinx=0\sin(3x)+\sin x = 0: applying the sum-to-product formula it becomes 2sin(2x)cosx=02\sin(2x)\cos x = 0, which by the zero-product law splits into the two elementary equations sin(2x)=0\sin(2x)=0 and cosx=0\cos x=0.

Topics: Prostaferesi werner
Concepts: Formule di prostaferesi · Legge di annullamento del prodotto
Functions: Coseno · Seno
Methods: Formule prostaferesi
Skills: Scomporre · Usare formule