Statement A population grows by 3%3\%3% each year starting from 500005000050000 inhabitants. After how many years will it exceed 800008000080000? Solution 50000 (1.03)n>80000⇒(1.03)n>1.650000\,(1{.}03)^{n}>80000\Rightarrow (1{.}03)^{n}>1{.}650000(1.03)n>80000⇒(1.03)n>1.6. n>ln1.6ln1.03=0.4700040.029559≈15.90⇒n=16 years.n>\frac{\ln 1{.}6}{\ln 1{.}03}=\frac{0{.}470004}{0{.}029559}\approx 15{.}90\Rightarrow\boxed{n=16\ \text{years}}.n>ln1.03ln1.6=0.0295590.470004≈15.90⇒n=16 years.