Statement In how many years does a capital quadruple at 8%8\%8% with continuous compounding? Solution e0.08 t=4⇒t=ln40.08=1.3862940.08≈17.33 years.e^{0{.}08\,t}=4\Rightarrow t=\dfrac{\ln 4}{0{.}08}=\dfrac{1{.}386294}{0{.}08}\approx\boxed{17{.}33\ \text{years}}.e0.08t=4⇒t=0.08ln4=0.081.386294≈17.33 years.