Statement In how many years does a capital double at 6%6\%6% per year with compound interest? Solution From (1.06)t=2(1{.}06)^{t}=2(1.06)t=2 we get tln1.06=ln2t\ln 1{.}06=\ln 2tln1.06=ln2. t=ln2ln1.06=0.6931470.058269≈11.90 years.t=\frac{\ln 2}{\ln 1{.}06}=\frac{0{.}693147}{0{.}058269}\approx\boxed{11{.}90\ \text{years}}.t=ln1.06ln2=0.0582690.693147≈11.90 years.