Statement At what annual rate does a capital double in 121212 years with annual compounding? Solution From C (1+i)12=2CC\,(1+i)^{12}=2CC(1+i)12=2C we get (1+i)12=2(1+i)^{12}=2(1+i)12=2, so 1+i=21/121+i=2^{1/12}1+i=21/12. 1+i=eln212=e0.057762=1.059463⇒i≈5.95%.1+i=e^{\frac{\ln 2}{12}}=e^{0{.}057762}=1{.}059463\Rightarrow i\approx\boxed{5{.}95\%}.1+i=e12ln2=e0.057762=1.059463⇒i≈5.95%.