Statement How many years are needed for 8000 €8000\ \text{€}8000 € to become 20 000 €20\,000\ \text{€}20000 € at 7%7\%7% compounded annually? Solution From 8000 (1.07)n=20 0008000\,(1{.}07)^{n} = 20\,0008000(1.07)n=20000 it follows 1.07n=2.51{.}07^{n} = 2{.}51.07n=2.5. n=ln2.5ln1.07=0.9162910.067659≈13.54 years.n = \frac{\ln 2{.}5}{\ln 1{.}07} = \frac{0{.}916291}{0{.}067659} \approx \boxed{13{.}54\ \text{years}}.n=ln1.07ln2.5=0.0676590.916291≈13.54 years.