Text A bacterial culture doubles its number of cells every 444 hours and starts from 500500500 cells. (a) How many cells are there after 242424 hours? (b) After how long does the culture reach 10 00010\,00010000 cells? Solution The model is N(t)=500⋅2 t/4N(t)=500\cdot 2^{\,t/4}N(t)=500⋅2t/4, with ttt in hours. (a) N(24)=500⋅224/4=500⋅26=500⋅64=32 000N(24)=500\cdot 2^{24/4}=500\cdot 2^{6}=500\cdot 64=32\,000N(24)=500⋅224/4=500⋅26=500⋅64=32000 cells. (b) Impose 500⋅2 t/4=10 000500\cdot 2^{\,t/4}=10\,000500⋅2t/4=10000, i.e. 2 t/4=202^{\,t/4}=202t/4=20. Taking base-222 logarithms: t4=log220=ln20ln2≈4.322 ⇒ t≈17.29 h.\frac{t}{4}=\log_2 20=\frac{\ln 20}{\ln 2}\approx 4.322\;\Rightarrow\; t\approx 17.29\ \text{h}.4t=log220=ln2ln20≈4.322⇒t≈17.29 h. N(24)=32 000 cells,t≈17.29 h \boxed{\,N(24)=32\,000\ \text{cells},\quad t\approx 17.29\ \text{h}\,}N(24)=32000 cells,t≈17.29 h