Statement How much must be invested today at 6%6\%6% compounded annually to have 10 000 €10\,000\ \text{€}10000 € in 555 years? Solution From M=C (1+i)nM = C\,(1+i)^nM=C(1+i)n we get C=M (1+i)−nC = M\,(1+i)^{-n}C=M(1+i)−n. C=10 000⋅1.06−5=10 0001.338226≈7472.58 €.C = 10\,000\cdot 1{.}06^{-5} = \frac{10\,000}{1{.}338226} \approx \boxed{7472{.}58\ \text{€}}.C=10000⋅1.06−5=1.33822610000≈7472.58 €.