Linear demand. Through (300;20) and (500;2) the slope is 500−3002−20=−1009, so
q(p)=20−1009(p−300)=47−1009p.
(a) Profit is π(p)=(p−100)q(p)=(p−100)(47−1009p): a downward parabola vanishing at p=100 and p=94700≈522,2. The maximum is at the vertex, halfway between the zeros:
p∗∗=2100+94700=92800≈311,11 €.
There q=19 and π=(92800−100)⋅19=936100≈4011,11 €/month.
(b) With the tax the unit revenue is 43p, so π(p)=(43p−100)(47−1009p). Zeros at p=3400≈133,3 and p=94700; the vertex is at
p∗∗=23400+94700=92950≈327,78 €.
p2025≈311,11 €,πmax≈4011,11 €,p2026≈327,78 €