Text Let f(x)=2x+1f(x)=2x+1f(x)=2x+1 and g(x)=x2g(x)=x^{2}g(x)=x2. Write f(g(x))f(g(x))f(g(x)) and g(f(x))g(f(x))g(f(x)) and evaluate them at x=2x=2x=2. Solution f(g(x))=2x2+1f(g(x))=2x^{2}+1f(g(x))=2x2+1 and g(f(x))=(2x+1)2=4x2+4x+1g(f(x))=(2x+1)^{2}=4x^{2}+4x+1g(f(x))=(2x+1)2=4x2+4x+1. At x=2x=2x=2: f(g(2))=2⋅4+1=9f(g(2))=2\cdot 4+1=9f(g(2))=2⋅4+1=9 and g(f(2))=(5)2=25g(f(2))=(5)^{2}=25g(f(2))=(5)2=25. (f∘g)(2)=9,(g∘f)(2)=25 \boxed{\,(f\circ g)(2)=9,\quad (g\circ f)(2)=25\,}(f∘g)(2)=9,(g∘f)(2)=25