Text Find the domain of: f(x)=x−3x−5.f(x)=\frac{\sqrt{x-3}}{x-5}.f(x)=x−5x−3. Solution Two conditions are needed: radicand ≥0\ge 0≥0 and denominator ≠0\neq 0=0: x−3≥0 and x−5≠0 ⇒ x≥3 and x≠5.x-3\ge 0\ \text{and}\ x-5\neq 0\;\Rightarrow\; x\ge 3\ \text{and}\ x\neq 5.x−3≥0 and x−5=0⇒x≥3 and x=5. D=[3,5)∪(5,+∞) \boxed{\,D=[3,5)\cup(5,+\infty)\,}D=[3,5)∪(5,+∞)