(a) Vertical asymptote x=−4; horizontal asymptote y=−3. Centre C(−4;−3).
(b)y(x+4)=2−3x⇒(x+4)(y+3)=14.
(c) It is a rectangular hyperbola with k=14>0: the vertices lie on the bisector y+3=x+4, with (x+4)2=14, i.e. V(−4±14;−3±14). Semi-axes a=b=2k=27, c=214; foci F(−4±27;−3±27).