Text Three points divide a circle into three arcs of length 25.1325.1325.13 cm, 37.7037.7037.70 cm and 62.8362.8362.83 cm respectively. Find the radius of the circle and the three corresponding central angles. Solution The sum of the arcs equals the circumference: 25.13+37.70+62.83=125.66=2πr ⟹ r=125.662π≈20 cm.25.13+37.70+62.83=125.66=2\pi r\ \Longrightarrow\ r=\frac{125.66}{2\pi}\approx20\ \text{cm}.25.13+37.70+62.83=125.66=2πr ⟹ r=2π125.66≈20 cm. The central angles are proportional to the arcs (2:3:52:3:52:3:5, total 101010): α1=210⋅360∘=72∘,α2=108∘,α3=180∘.\alpha_1=\frac{2}{10}\cdot360^\circ=72^\circ,\quad \alpha_2=108^\circ,\quad \alpha_3=180^\circ.α1=102⋅360∘=72∘,α2=108∘,α3=180∘. r=20 cm; 72∘, 108∘, 180∘\boxed{r=20\ \text{cm};\ \ 72^\circ,\ 108^\circ,\ 180^\circ}r=20 cm; 72∘, 108∘, 180∘