Text Find the parabola y=ax2+bx+cy=ax^{2}+bx+cy=ax2+bx+c through A(0,3)A(0,3)A(0,3), B(1,2)B(1,2)B(1,2), C(−1,6)C(-1,6)C(−1,6). Solution From AAA: c=3c=3c=3. From BBB: a+b+3=2⇒a+b=−1a+b+3=2\Rightarrow a+b=-1a+b+3=2⇒a+b=−1. From CCC: a−b+3=6⇒a−b=3a-b+3=6\Rightarrow a-b=3a−b+3=6⇒a−b=3. Adding: 2a=2⇒a=12a=2\Rightarrow a=12a=2⇒a=1, hence b=−2b=-2b=−2. y=x2−2x+3 \boxed{\,y=x^{2}-2x+3\,}y=x2−2x+3