Text Given y=2(x−1)2−8y=2(x-1)^{2}-8y=2(x−1)2−8, find the vertex and the xxx-intercepts. Solution From vertex form the vertex is V(1,−8)V(1,-8)V(1,−8). xxx-intercepts: 2(x−1)2−8=0⇒(x−1)2=4⇒x−1=±22(x-1)^{2}-8=0\Rightarrow (x-1)^{2}=4\Rightarrow x-1=\pm 22(x−1)2−8=0⇒(x−1)2=4⇒x−1=±2, so x=3x=3x=3 or x=−1x=-1x=−1. V(1,−8),(−1,0), (3,0) \boxed{\,V(1,-8),\quad (-1,0),\ (3,0)\,}V(1,−8),(−1,0), (3,0)