Text Given the parabola y=x2−6x+5y=x^{2}-6x+5y=x2−6x+5, find the vertex by completing the square. Solution Complete the square: y=(x2−6x+9)−9+5=(x−3)2−4.y=(x^{2}-6x+9)-9+5=(x-3)^{2}-4.y=(x2−6x+9)−9+5=(x−3)2−4. The vertex is V(3,−4)V(3,-4)V(3,−4). V(3, −4) \boxed{\,V(3,\,-4)\,}V(3,−4)