Text Solve the system of inequalities {∣x∣<3x2−x−2>0.\begin{cases}|x|<3\\ x^2-x-2>0.\end{cases}{∣x∣<3x2−x−2>0. Solution First: ∣x∣<3 ⟹ −3<x<3|x|<3\implies -3<x<3∣x∣<3⟹−3<x<3. Second: x2−x−2=(x−2)(x+1)>0 ⟹ x<−1 ∨ x>2x^2-x-2=(x-2)(x+1)>0\implies x<-1\ \vee\ x>2x2−x−2=(x−2)(x+1)>0⟹x<−1 ∨ x>2. Intersecting the two sets: −3<x<−1 ∨ 2<x<3.\boxed{-3<x<-1\ \vee\ 2<x<3.}−3<x<−1 ∨ 2<x<3.