Sistema di disequazioni $\{x^2-16<0;\ x-1>0\}$

Text

Solve the system of inequalities $\begin{cases}x^2-16<0\\ x-1>0.\end{cases}$

Solution

First inequality: $x^2<16\implies -4<x<4$. Second inequality: $x>1$. Intersecting the two solution sets: $\boxed{1<x<4.}$