Text Solve: 2x2−5x−3<0.2x^{2}-5x-3<0.2x2−5x−3<0. Solution Zeros: 2x2−5x−3=(2x+1)(x−3)=0⇒x=−12, x=32x^{2}-5x-3=(2x+1)(x-3)=0\Rightarrow x=-\tfrac12,\ x=32x2−5x−3=(2x+1)(x−3)=0⇒x=−21, x=3. Opens upward: <0<0<0 between the roots: −12<x<3.-\tfrac12<x<3.−21<x<3. −12<x<3 \boxed{\,-\tfrac12<x<3\,}−21<x<3