Text Solve: x2−x−6≥0.x^{2}-x-6\ge 0.x2−x−6≥0. Solution Zeros: x2−x−6=(x−3)(x+2)=0⇒x=3, x=−2x^{2}-x-6=(x-3)(x+2)=0\Rightarrow x=3,\ x=-2x2−x−6=(x−3)(x+2)=0⇒x=3, x=−2. The parabola opens upward, so it is ≥0\ge 0≥0 outside the roots: x≤−2 or x≥3.x\le -2\ \text{or}\ x\ge 3.x≤−2 or x≥3. x≤−2 ∨ x≥3 \boxed{\,x\le -2\ \vee\ x\ge 3\,}x≤−2 ∨ x≥3