Statement Solve using the quadratic formula: (a) 3x2−7x+2=03x^2-7x+2=03x2−7x+2=0 (b) 2x2+5x−12=02x^2+5x-12=02x2+5x−12=0 Solution (a) Δ=49−24=25\Delta=49-24=25Δ=49−24=25, x=7±56x=\dfrac{7\pm 5}{6}x=67±5, so x=2x=2x=2 or x=13x=\dfrac13x=31. (b) Δ=25+96=121\Delta=25+96=121Δ=25+96=121, x=−5±114x=\dfrac{-5\pm 11}{4}x=4−5±11, so x=32x=\dfrac32x=23 or x=−4x=-4x=−4. xa=2, 13;xb=32, −4\boxed{x_a=2,\ \tfrac13;\qquad x_b=\tfrac32,\ -4}xa=2, 31;xb=23, −4