Text Combine into a single fraction: 3x−2+5x+2.\frac{3}{x-2}+\frac{5}{x+2}.x−23+x+25. Solution Common denominator (x−2)(x+2)=x2−4(x-2)(x+2)=x^{2}-4(x−2)(x+2)=x2−4: 3(x+2)+5(x−2)x2−4=3x+6+5x−10x2−4=8x−4x2−4,x≠±2.\frac{3(x+2)+5(x-2)}{x^{2}-4}=\frac{3x+6+5x-10}{x^{2}-4}=\frac{8x-4}{x^{2}-4},\qquad x\neq\pm 2.x2−43(x+2)+5(x−2)=x2−43x+6+5x−10=x2−48x−4,x=±2. 4(2x−1)x2−4(x≠±2) \boxed{\,\dfrac{4(2x-1)}{x^{2}-4}\quad (x\neq\pm 2)\,}x2−44(2x−1)(x=±2)