Text Compute and simplify: x2−1x⋅3xx+1.\frac{x^{2}-1}{x}\cdot\frac{3x}{x+1}.xx2−1⋅x+13x. Solution Factorise x2−1=(x−1)(x+1)x^{2}-1=(x-1)(x+1)x2−1=(x−1)(x+1) and cancel: (x−1)(x+1)x⋅3xx+1=3(x−1)=3x−3,x≠0, x≠−1.\frac{(x-1)(x+1)}{x}\cdot\frac{3x}{x+1}=3(x-1)=3x-3,\qquad x\neq 0,\ x\neq -1.x(x−1)(x+1)⋅x+13x=3(x−1)=3x−3,x=0, x=−1. 3x−3(x≠0, −1) \boxed{\,3x-3\quad (x\neq 0,\,-1)\,}3x−3(x=0,−1)