Observation — Triangle diagram for (A+B+C)2(A+B+C)^2

To recognise whether a 6-term polynomial is a square of a trinomial, a triangle diagram is used: the squares of the three terms at the vertices, the double products on the sides.

At the vertices the squares of the terms, on the sides their double products.

Example. 1+4t2+4z24t+4z8tz1+4t^2+4z^2-4t+4z-8tz. I suspect a square of a trinomial.

  • Vertices: 1=(1)21 = (1)^2,   4t2=(2t)2\;4t^2 = (2t)^2,   4z2=(2z)2\;4z^2 = (2z)^2.
  • Sides: 212t=4t2\cdot 1\cdot 2t = 4t? The term is 4t-4t, so the sign is -.
  • 212z=4z2\cdot 1\cdot 2z = 4z. ✓
  • 22t2z=8tz2\cdot 2t\cdot 2z = 8tz? The term is 8tz-8tz, so the sign is -.

Therefore 1+4t2+4z24t+4z8tz=(12t+2z)21+4t^2+4z^2-4t+4z-8tz = \boxed{(1-2t+2z)^2}.

Topics: Algebraic calculus
Concepts: Special products · Square of a trinomial
Skills: Using formulas